solve using MOMENT AREA METHOD Transcribed Image Text: O Pab 2l -b) PL 3EI PL? Og = 2EI PL PL? 16EI Px2 (3L² – 4x*)

solve using MOMENT AREA METHOD Transcribed Image Text: O Pab 2l -b)
PL
3EI
PL?
Og =
2EI
PL
PL?
16EI
Px2
(3L² – 4x*) 0 sxs
48EI
48EI
6E 3L – x)
Ph(L –
9/3LEI
Phx
(L -x – b)
OSxsa
Px2
GLEI
-(21 – a)
Pab
6L EI
E (3a – x) 0Sxsa
B
6EI
Pa?
dn =AE (3L – a)
Og =-
Pa
Pb (L.
at xV
Pah
6EI
2EI
(21 -b)
6LEI
Pa?
(3x- a) a SXSL
6EI
Ph
(31-46) if a >b
SaerT
48EI
Swl
(L’- 21.x +x’)
Smar
384EI
– – AEI
24EI
-(6L – 4Lx+x²)
OB =
6EI
24EI
SEI
2L Ela – 21)² + 2a(a – 21.)x + Lx daer (S2 – 121b+ 84y
241. EI
(SL – 121b + 8A)
384EI
(a – 2L)
Wo
OSxsa
241. EI
if a zb
ME(6a – 4ax+x) 0sxs a
24EI
Woa
24ET AL – a) Og =-
(-L+x)(a – 4Lx + 2x)
Santer
KET (3L – 2a) if asb 34LET (21. -a”)
(31 – 2a) if a sb
24L. EI
6EI
24L. EI
96EI
Wpa”
24E (4x – a)
asxsL
da 0.006 522

El
360EI
(7L* – 102x² + 3x*)
at x- 0.51931
360LEI
Sio “L
Sar-0.006 510
EI
45 EI
woL
A
120L ET (10L’ – 10L²X+5Lx² – x³) | ôp =
24EI
30EI
at xA
Max
(L-x)
6LEI
E19 va
Mol
9/3EI
6EI
MoL
Mox?
Saner
MoL
Og =
EI
16EI
3EI
Mo
2EI
2EI

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